Leetcode 718: Maximum Length of Repeated Subarray

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grid47
Exploring patterns and algorithms
Aug 27, 2024 6 min read

An array where the longest repeated subarray is highlighted and softly glowing as it's determined.
Solution to LeetCode 718: Maximum Length of Repeated Subarray Problem

Given two integer arrays nums1 and nums2, your task is to find the maximum length of a contiguous subarray that appears in both arrays.
Problem
Approach
Steps
Complexity
Input: The input consists of two arrays `nums1` and `nums2` of integers.
Example: nums1 = [4, 5, 6, 7, 8], nums2 = [1, 2, 3, 4, 5]
Constraints:
• 1 <= nums1.length, nums2.length <= 1000
• 0 <= nums1[i], nums2[i] <= 100
Output: Return the maximum length of a contiguous subarray that appears in both `nums1` and `nums2`.
Example: 2
Constraints:
• The result should be a non-negative integer representing the length of the longest common subarray.
Goal: To compute the maximum length of a contiguous subarray that appears in both arrays using dynamic programming.
Steps:
• Create a 2D array `dp` where `dp[i][j]` represents the length of the longest common subarray ending at `nums1[i-1]` and `nums2[j-1]`.
• If `nums1[i-1] == nums2[j-1]`, then `dp[i][j] = dp[i-1][j-1] + 1`.
• Track the maximum value in the `dp` array during the iteration.
Goal: The solution should efficiently handle large inputs up to 1000 elements in both arrays.
Steps:
• The input arrays `nums1` and `nums2` have lengths up to 1000.
• Each element in `nums1` and `nums2` is between 0 and 100.
Assumptions:
• The input arrays will contain non-negative integers.
• The length of the arrays is guaranteed to be at least 1.
Input: nums1 = [4, 5, 6, 7, 8], nums2 = [1, 2, 3, 4, 5]
Explanation: The longest common subarray is [4, 5], which has a length of 2.

Input: nums1 = [1, 2, 3, 4], nums2 = [2, 3, 4, 5]
Explanation: The longest common subarray is [2, 3, 4], which has a length of 3.

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