Leetcode 385: Mini Parser
Given a string s representing a serialized nested list, implement a parser to deserialize it and return the deserialized NestedInteger.
Problem
Approach
Steps
Complexity
Input: The input is a string s representing the serialized nested list.
Example: s = '[789, [1011, 1213], 1415]'
Constraints:
• 1 <= s.length <= 50,000
• s consists of digits, square brackets '[]', negative sign '-', and commas ','
• The string s is the serialization of a valid NestedInteger
• All values are within the range [-10^6, 10^6]
Output: The output is a NestedInteger object representing the deserialized nested list.
Example: Output: [789, [1011, 1213], 1415]
Constraints:
• The deserialized object should match the nested list structure.
Goal: The goal is to parse the serialized string and reconstruct the correct NestedInteger object.
Steps:
• Traverse the string character by character.
• Identify numbers and handle their potential negative signs.
• Identify opening brackets '[' and create new NestedInteger objects for lists.
• Identify closing brackets ']' and complete the current list.
• Use a stack to maintain the current state while parsing nested lists.
Goal: The solution must be efficient to handle large inputs.
Steps:
• The solution should handle up to 50,000 characters in the input string efficiently.
Assumptions:
• The input string is a valid serialized NestedInteger and will not contain malformed lists.
• Input: Input: '[789, [1011, 1213], 1415]'
• Explanation: The string represents a list with three elements: 789, a nested list [1011, 1213], and 1415.
Approach: The approach involves parsing the string to correctly build a NestedInteger object, using a stack to handle nested lists and ensuring that each element is correctly identified as an integer or list.
Observations:
• We need to distinguish between integers and lists while parsing the string.
• A stack will be useful to manage the nesting of lists during parsing.
Steps:
• Initialize an empty stack.
• Iterate through each character of the string.
• When encountering a number, extract the number and add it as a NestedInteger.
• When encountering a '[' symbol, push a new NestedInteger (representing a new list) onto the stack.
• When encountering a ']' symbol, pop the top of the stack and add it to the NestedInteger object beneath it.
Empty Inputs:
• Ensure that input strings are non-empty and valid.
Large Inputs:
• Handle input strings as large as 50,000 characters efficiently.
Special Values:
• Ensure the solution handles negative numbers and deep nesting correctly.
Constraints:
• The solution must parse the string in linear time relative to its length.
NestedInteger deserialize(string s) {
function<bool(char)> isnumber = [](char c) { return (c == '-') || isdigit(c); };
stack<NestedInteger> stk;
stk.push(NestedInteger());
for(auto it = s.begin(); it != s.end();) {
const char &c = *it;
if(isnumber(c)) {
auto it2 = find_if_not(it, s.end(), isnumber);
int val = stoi(string(it, it2));
stk.top().add(NestedInteger(val));
it = it2;
}
else {
if(c == '[') {
stk.push(NestedInteger());
} else if (c == ']') {
NestedInteger ni = stk.top();
stk.pop();
stk.top().add(ni);
}
it++;
}
}
NestedInteger res = stk.top().getList().front();
return res;
}
1 : Function Definition
NestedInteger deserialize(string s) {
This is the function definition of 'deserialize' which takes a string 's' as input and returns a NestedInteger object.
2 : Lambda Function
function<bool(char)> isnumber = [](char c) { return (c == '-') || isdigit(c); };
This lambda function checks if a character is a number (including negative sign).
3 : Stack Initialization
stack<NestedInteger> stk;
A stack to store NestedInteger objects which will help in building the deserialized structure.
4 : Push Operation
stk.push(NestedInteger());
Push an empty NestedInteger to the stack as the starting point for building the structure.
5 : Iterator
for(auto it = s.begin(); it != s.end();) {
A for-loop to iterate through each character in the string 's'.
6 : Character Access
const char &c = *it;
Access the current character of the string 's'.
7 : Check for Number
if(isnumber(c)) {
Check if the current character is a number (either positive or negative).
8 : Find Non-Number
auto it2 = find_if_not(it, s.end(), isnumber);
Find the first character in the string 's' that is not a number.
9 : Integer Conversion
int val = stoi(string(it, it2));
Convert the substring representing a number into an integer.
10 : Add to Stack
stk.top().add(NestedInteger(val));
Add the integer value as a NestedInteger object to the top of the stack.
11 : Update Iterator
it = it2;
Update the iterator to the next non-number character.
12 : Else Block
else {
If the character is not a number, check for the special characters '[' or ']'.
13 : Opening Bracket Check
if(c == '[') {
Check if the character is an opening bracket '[' which indicates the start of a new list.
14 : Push New NestedInteger
stk.push(NestedInteger());
Push a new empty NestedInteger to the stack to represent the new list.
15 : Closing Bracket Check
} else if (c == ']') {
Check if the character is a closing bracket ']' which indicates the end of a list.
16 : Pop and Add to Parent
NestedInteger ni = stk.top();
Pop the top NestedInteger object from the stack.
17 : Pop Stack
stk.pop();
Pop the top element from the stack after storing it in 'ni'.
18 : Add to Parent List
stk.top().add(ni);
Add the popped NestedInteger object to the top NestedInteger in the stack.
19 : Increment Iterator
it++;
Increment the iterator to move to the next character in the string.
20 : Return Result
NestedInteger res = stk.top().getList().front();
Get the first element from the list in the top NestedInteger object in the stack.
21 : Return Result
return res;
Return the deserialized NestedInteger object.
Best Case: O(n)
Average Case: O(n)
Worst Case: O(n)
Description: The time complexity is linear with respect to the length of the input string.
Best Case: O(n)
Worst Case: O(n)
Description: The space complexity is O(n) due to the space required for the stack and NestedInteger objects.
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