You are given a label representing a node in an infinite binary tree. In this binary tree, each level alternates between left-to-right and right-to-left labeling. Your task is to return the path from the root of the tree to the node with the given label, following the zigzag pattern.
You are given an array of books where each book is represented by a pair of integers [thickness, height]. Additionally, you have a shelf with a fixed width. Your goal is to arrange the books on the shelves such that each shelf’s total thickness is less than or equal to the shelf width, and the height of each shelf is determined by the tallest book placed on it. The books must be placed in the same order as they appear in the input array. The objective is to minimize the total height of the bookshelf.
You are given a list of flight bookings, where each booking specifies the flight range (from first flight to last flight) and the number of seats reserved for each of the flights in that range. You need to compute the total number of seats reserved for each flight, from flight 1 to flight n.
Given the root of a binary tree, and a list of values to delete, your task is to remove the nodes with the given values. The resulting tree will become a forest, where each tree is a disjoint set of nodes. Return the roots of the trees in the remaining forest.
A string consisting of only ‘(’ and ‘)’ characters is considered a valid parentheses string (VPS) if it satisfies the following conditions: it is empty, can be split into two valid VPS’s, or can be written in the form of ‘(A)’ where A is a VPS. You are given a VPS string seq. The task is to split it into two subsequences, A and B, such that both A and B are valid parentheses strings. The goal is to minimize the maximum nesting depth between A and B, and you need to return an array where each element is 0 if the character is part of A, and 1 if it’s part of B.
You are given a class FooBar with two methods: foo() and bar(). These methods are called concurrently by two threads. One thread calls foo() while the other calls bar(). You need to modify the program to ensure that the output alternates between ‘foo’ and ‘bar’, and ‘foobar’ is printed exactly n times. The threads should alternate their execution such that foo() is printed first, followed by bar(), and this pattern should continue for n times.